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Proof step 6 from proof fits-law-bxor-02 (previous step)

⊦ bor(band(s2i(sho1), bcompl(s2i(sho2))), band(bcompl(s2i(sho1)), s2i(sho2))) = s2i(i2s(bor(band(s2i(sho1), bcompl(s2i(sho2))), band(bcompl(s2i(sho1)), s2i(sho2))))), band(s2i(sho1), bcompl(s2i(sho2))) ∈short ∧ band(bcompl(s2i(sho1)), s2i(sho2)) ∈short

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ i ∈short ↔ s2i(i2s(i)) = i
Proof step 8:
⊦ bor(band(s2i(sho1), bcompl(s2i(sho2))), band(bcompl(s2i(sho1)), s2i(sho2))) = s2i(i2s(bor(band(s2i(sho1), bcompl(s2i(sho2))), band(bcompl(s2i(sho1)), s2i(sho2))))), s2i(i2s(band(s2i(sho1), bcompl(s2i(sho2))))) = band(s2i(sho1), bcompl(s2i(sho2))) ∧ band(bcompl(s2i(sho1)), s2i(sho2)) ∈short

Rule argument

name: inshort-sis rotate: F subst: [i] → [band(s2i(sho1), bcompl(s2i(sho2)))]

Additional information

Used terms: band(s2i(sho1), bcompl(s2i(sho2)))