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Proof step 5 from proof fits-law-compl-01 (previous step)

¬ n→i(# int2bits(bcompl(s2i(sho)))) ≤ 16 ⊦ bcompl(s2i(sho)) = cast(16, bcompl(s2i(sho)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
16 < # int2bits(bcompl(s2i(sho))) ⊦ bcompl(s2i(sho)) = cast(16, bcompl(s2i(sho)))

Rule argument

Additional information

Used simplifier rules: ⊦ int2bits(j) ≠ [];% ⊦ # bits = 0 ↔ bits = [];% ⊦ m < n → n ≠ 0; (forward)% ⊦ ¬ m ≤ n ↔ n < m;%0 ≤ i ⊦ n→i(n) ≤ (* i) ↔ n ≤ i→n(i);