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Proof step 6 from proof fits-law-compl-01 (previous step)

16 < # int2bits(bcompl(s2i(sho))) ⊦ bcompl(s2i(sho)) = cast(16, bcompl(s2i(sho)))

User applied rule cut formula

And obtained the following new goals

Proof step 7:
# int2bits(bcompl(s2i(sho))) ≤ # int2bits(s2i(sho)), 16 < # int2bits(bcompl(s2i(sho))) ⊦ bcompl(s2i(sho)) = cast(16, bcompl(s2i(sho)))

Rule argument

fma: # int2bits(bcompl(s2i(sho))) ≤ # int2bits(s2i(sho))

Additional information

Used simplifier rules: ⊦ ¬ m ≤ n ↔ n < m;% ⊦ ¬ # int2bits(i) < # int2bits(bcompl(i)); Used formulas: # int2bits(bcompl(s2i(sho))) ≤ # int2bits(s2i(sho))