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Proof step 13 from proof fits-law-div (previous step)

i ≠ ~1 → b2i(by1) / i = b2i(i2b(b2i(by1) / i)) ⊦ i ≠ ~1, i = 0, b2i(by1) / i = s2i(i2s(b2i(by1) / i))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ ~ i = j ↔ i + j = 0;% ⊦ i / ~1 = ~ i;