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Proof step 5 from proof fits-law-div (previous step)

i ≠ ~1 → b2i(by1) / i = b2i(i2b(b2i(by1) / i)) ⊦ i = 0, b2i(by1) / i = s2i(i2s(b2i(by1) / i))

User applied rule cut formula

And obtained the following new goals

Proof step 6:
i ≠ ~1, i ≠ ~1 → b2i(by1) / i = b2i(i2b(b2i(by1) / i)) ⊦ i = 0, b2i(by1) / i = s2i(i2s(b2i(by1) / i))
Proof step 13:
i ≠ ~1 → b2i(by1) / i = b2i(i2b(b2i(by1) / i)) ⊦ i ≠ ~1, i = 0, b2i(by1) / i = s2i(i2s(b2i(by1) / i))

Rule argument

fma: i ≠ ~1

Additional information

Used formulas: i ≠ ~1