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Proof step 4 from proof fits-law-div (
previous step
)
i ≠ ~1 ∧ i ≠ 0 → b2i(by1) / i = b2i(i2b(b2i(by1) / i)) ⊦ i = 0, b2i(by1) / i = s2i(i2s(b2i(by1) / i))
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 5
:
i ≠ ~1 → b2i(by1) / i = b2i(i2b(b2i(by1) / i)) ⊦ i = 0, b2i(by1) / i = s2i(i2s(b2i(by1) / i))
Rule argument
Additional information