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Proof step 12 from proof fits-law-mod (previous step)

129 < abs(b2i(by1)), i % b2i(by1) < b2i(by1), i % b2i(by1) < 0, i < 0, i % b2i(by1) < ~128 ⊦ i % b2i(by1) = b2i(i2b(i % b2i(by1))), b2i(by1) = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ j < 0 → abs(j) = 0 - j subst: [j] → [b2i(by1)] rotate: F spec: int-abs inst: name: Abs-neg

Additional information

Used simplifier rules: byte-ngr: i ≥ 127 ⊦ ¬ (* i) < b2i(by);%byte-nls-01: i ≤ ~128 ⊦ ¬ b2i(by) < (* i);% ⊦ ¬ j < 0 → abs(j) = j;% ⊦ ¬ i < j → (i ≠ j ↔ j < i);% ⊦ 0 - i = ~ i;% ⊦ i < ~ j ↔ i + j < 0;% ⊦ i + (* j) < (* j0) ↔ i < j0 - j;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i; Used terms: b2i(by1)