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Proof step 11 from proof fits-law-mod (previous step)

¬(~128 - 1 ≤ ~ abs(b2i(by1)) ∧ b2i(by1) ≠ 0), i % b2i(by1) < ~128, i < 0, i % b2i(by1) < 0, i % b2i(by1) < b2i(by1) ⊦ b2i(by1) = 0, i % b2i(by1) = b2i(i2b(i % b2i(by1)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: i0 ≠ 0, i0 < i ⊦ (* i) < j → (* i0) < j;% ⊦ 0 < abs(i) ↔ i ≠ 0;% ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward)% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i - j ≤ i0 ↔ i ≤ j + i0;% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;%i < 0 ⊦ (* i) + j = j - ~ i;% ⊦ i ≤ ~ j ↔ i + j ≤ 0;