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Proof step 9 from proof fits-law-mod (previous step)

i % b2i(by1) < ~128, i < 0, i % b2i(by1) < 0, i % b2i(by1) < b2i(by1) ⊦ b2i(by1) = 0, i % b2i(by1) = b2i(i2b(i % b2i(by1)))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 10:
⊦ i0 - 1 ≤ ~ abs(j) ∧ j ≠ 0 → ¬ i % j < i0
Proof step 11:
¬(~128 - 1 ≤ ~ abs(b2i(by1)) ∧ b2i(by1) ≠ 0), i % b2i(by1) < ~128, i < 0, i % b2i(by1) < 0, i % b2i(by1) < b2i(by1) ⊦ b2i(by1) = 0, i % b2i(by1) = b2i(i2b(i % b2i(by1)))

Rule argument

seq: ⊦ i0 - 1 ≤ ~ abs(j) ∧ j ≠ 0 → ¬ i % j < i0 subst: [i0, j, i] → [~128, b2i(by1), i] rotate: F spec: int-div inst: name: mod-nls-04

Additional information

Used terms: ~128, b2i(by1), i