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Proof step 8 from proof fits-law-mod (previous step)

i % b2i(by1) < ~128, i < 0, i % b2i(by1) < 0 ⊦ b2i(by1) ≤ i % b2i(by1), b2i(by1) = 0, i % b2i(by1) = b2i(i2b(i % b2i(by1)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
i % b2i(by1) < ~128, i < 0, i % b2i(by1) < 0, i % b2i(by1) < b2i(by1) ⊦ b2i(by1) = 0, i % b2i(by1) = b2i(i2b(i % b2i(by1)))

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ i ≤ j ↔ j < i;