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Proof step 1 from proof fits-law-neg (conclusion)

⊦ ~ b2i(by) = s2i(i2s(~ b2i(by)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ b2i(by) + s2i(i2s(~ b2i(by))) = 0

Rule argument

Additional information

Used simplifier rules: ⊦ ~ i = j ↔ i + j = 0;