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Proof step 2 from proof fits-law-neg (previous step)

⊦ b2i(by) + s2i(i2s(~ b2i(by))) = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ s2i(i2s(i)) = cast(16, i)
Proof step 4:
⊦ b2i(by) + cast(16, ~ b2i(by)) = 0

Rule argument

name: short-is-cast rotate: F subst: [i] → [~ b2i(by)]

Additional information

Used terms: ~ b2i(by)