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Theorem i2b-equal

⊦ i2b(i) = i2b(j) ↔ b2i(i2b(i)) = b2i(i2b(j))

Type: A user defined theorem
Validity: The proof is valid.
Features:
Comment:
Used by: byte-is-cast-01, byte-law-and-one, byte-law-neg, byte-mult, byte-mult-256, byte-mult-neg, byte-mult-pos,
Used by units in proved state: bytes,
Proof exists?: Yes

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Infos about the proof

Proved?: Yes
Interactions: 0
Proof steps: 1
Used lemmas: byte-equal,
Used spec theorems:
- Used simplifier rules: