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Proof step 10 from proof long-eq (previous step)

¬ cast(64, cast(64, i)) ≠ l2i(i2l(cast(64, j))), i2l(cast(64, i)) = i2l(cast(64, j)) ⊦ cast(64, i) = cast(64, j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
i2l(cast(64, i)) = i2l(cast(64, j)), cast(64, i) = l2i(i2l(cast(64, j))) ⊦ cast(64, i) = cast(64, j)

Rule argument

Additional information

Used simplifier rules: ⊦ 0 < i → cast(i, cast(i, j)) = cast(i, j);