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Proof step 8 from proof long-eq (previous step)

¬ l2i(i2l(cast(64, i))) ≠ l2i(i2l(cast(64, j))), i2l(cast(64, i)) = i2l(cast(64, j)) ⊦ cast(64, i) = cast(64, j)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ l2i(i2l(i)) = cast(64, i)
Proof step 10:
¬ cast(64, cast(64, i)) ≠ l2i(i2l(cast(64, j))), i2l(cast(64, i)) = i2l(cast(64, j)) ⊦ cast(64, i) = cast(64, j)

Rule argument

name: long-is-cast rotate: F subst: [i] → [cast(64, i)]

Additional information

Used terms: cast(64, i)