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Proof step 6 from proof long-eq (previous step)

i2l(cast(64, i)) = i2l(cast(64, j)) ⊦ cast(64, i) = cast(64, j)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ l2i(i2l(i)) ≠ l2i(i2l(j)) → i2l(i) ≠ i2l(j)
Proof step 8:
¬ l2i(i2l(cast(64, i))) ≠ l2i(i2l(cast(64, j))), i2l(cast(64, i)) = i2l(cast(64, j)) ⊦ cast(64, i) = cast(64, j)

Rule argument

name: long-eq-01 rotate: F subst: [j, i] → [cast(64, j), cast(64, i)]

Additional information

Used terms: cast(64, j), cast(64, i)