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Proof step 14 from proof mod-inshort (previous step)

0 < s2i(sho0) % s2i(sho1), 32767 < s2i(sho0) % s2i(sho1) ⊦ 0 < s2i(sho1), s2i(sho1) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%ls-01: ⊦ i < j → ¬ j < i; from specification int-basic1%lst-01: ⊦ ¬ i < j → (i ≠ j ↔ j < i); from specification int-basic1