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Proof step 15 from proof mod-inshort (previous step)

0 < s2i(sho0) % s2i(sho1), 32767 < s2i(sho0) % s2i(sho1), s2i(sho1) < 0 ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 16:
⊦ i < 0 ∧ j < 0 → ¬ 0 < i % j
Proof step 17:
¬(s2i(sho0) < 0 ∧ s2i(sho1) < 0), 0 < s2i(sho0) % s2i(sho1), 32767 < s2i(sho0) % s2i(sho1), s2i(sho1) < 0 ⊦

Rule argument

spec: int-div inst: name: mod-grz-02 seq: ⊦ i < 0 ∧ j < 0 → ¬ 0 < i % j subst: [j, i] → [s2i(sho1), s2i(sho0)] flags: rewrite

Additional information

Used terms: s2i(sho1), s2i(sho0)