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Proof step 1 from proof num-i2b-equal (conclusion)
~128 ≤ i, i ≤ 127, ~128 ≤ j, j ≤ 127 ⊦ i2b((* i)) = i2b((* j)) ↔ i = j
Special step normalize
And obtained the following new goals
Proof step 2
:
~128 ≤ i, i ≤ 127, ~128 ≤ j, j ≤ 127 ⊦ i2b(i) = i2b(j) ↔ i = j