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Proof step 2 from proof num-i2b-equal (previous step)

~128 ≤ i, i ≤ 127, ~128 ≤ j, j ≤ 127 ⊦ i2b(i) = i2b(j) ↔ i = j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
i2b(i) = i2b(j), ~128 ≤ i, i ≤ 127, ~128 ≤ j, j ≤ 127 ⊦ i = j

Rule argument

Additional information

Used simplifier rules: ⊦ j ≤ j0 ∧ j0 ≤ j1 → j ≤ j1; (forward)