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Proof step 3 from proof short-equal (previous step)

i2s(s2i(shoi)) = shoi ⊦ s2i(shoi) = s2i(shoj) ↔ shoi = shoj

User applied rule insert lemma

And obtained the following new goals

Proof step 4:
⊦ i2s(s2i(sho)) = sho
Proof step 5:
i2s(s2i(shoj)) = shoj, i2s(s2i(shoi)) = shoi ⊦ s2i(shoi) = s2i(shoj) ↔ shoi = shoj

Rule argument

name: isi subst: [sho] → [shoj]

Additional information

Used terms: shoj