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Proof step 5 from proof short-equal (previous step)

i2s(s2i(shoj)) = shoj, i2s(s2i(shoi)) = shoi ⊦ s2i(shoi) = s2i(shoj) ↔ shoi = shoj

User applied rule case distinction

And obtained the following new goals

Proof step 6:
s2i(shoi) = s2i(shoj), i2s(s2i(shoj)) = shoj, i2s(s2i(shoi)) = shoi ⊦ shoi = shoj

Rule argument

pos: right 1

Additional information

Used simplifier rules: isi: ⊦ i2s(s2i(sho)) = sho;