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Proof step 4 from proof short-mod-01 (previous step)

¬(~32768 ≤ s2i(sho) % i ∧ s2i(sho) % i ≤ 32767) ⊦ i = 0, s2i(i2s(s2i(sho) % i)) = s2i(sho) % i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
⊦ i = 0, s2i(i2s(s2i(sho) % i)) = s2i(sho) % i, ¬ s2i(sho) % i < ~32768 ∧ ¬ 32767 < s2i(sho) % i

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ i ≤ j ↔ j < i;