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Proof step 5 from proof short-mod-01 (previous step)

⊦ i = 0, s2i(i2s(s2i(sho) % i)) = s2i(sho) % i, ¬ s2i(sho) % i < ~32768 ∧ ¬ 32767 < s2i(sho) % i

User applied rule case distinction

And obtained the following new goals

Proof step 6:
⊦ ¬ s2i(sho) % i < ~32768, i = 0, s2i(i2s(s2i(sho) % i)) = s2i(sho) % i
Proof step 9:
⊦ ¬ 32767 < s2i(sho) % i, i = 0, s2i(i2s(s2i(sho) % i)) = s2i(sho) % i

Rule argument

pos: right 3

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