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Proof step 6 from proof short-mod-01 (previous step)

⊦ ¬ s2i(sho) % i < ~32768, i = 0, s2i(i2s(s2i(sho) % i)) = s2i(sho) % i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
s2i(sho) % i < ~32768, s2i(sho) % i < 0 ⊦ i = 0, s2i(i2s(s2i(sho) % i)) = s2i(sho) % i

Rule argument

Additional information

Used simplifier rules: ⊦ i < (* j) ∧ j < 0 → i < 0; (forward)