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Proof step 4 from proof short-mod-add-01 (previous step)

¬ 0 ≤ s2i(sho), 0 ≤ s2i(sho) + s2i(sho0) ⊦ (s2i(sho) + s2i(sho0)) % 65536 = s2i(sho) + s2i(sho0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 ∧ 0 ≤ j → i < j;% ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ i < j ∧ j ≤ j0 → i < j0; (forward)% ⊦ ¬ i ≤ j ↔ j < i;