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Proof step 5 from proof short-mod-add-01 (previous step)

s2i(sho) < 0, 0 ≤ s2i(sho) + s2i(sho0) ⊦ (s2i(sho) + s2i(sho0)) % 65536 = s2i(sho) + s2i(sho0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ i + j = j + i
Proof step 7:
s2i(sho) < 0, 0 ≤ s2i(sho0) + s2i(sho) ⊦ (s2i(sho0) + s2i(sho)) % 65536 = s2i(sho0) + s2i(sho)

Rule argument

seq: ⊦ i + j = j + i subst: [j, i] → [s2i(sho0), s2i(sho)] rotate: F spec: int-basic2 inst: name: add-c

Additional information

Used terms: s2i(sho0), s2i(sho)