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Proof step 49 from proof sis-on-bits (previous step)

16 ≤ # int2bits(i) ⊦ ¬ 32767 < bits2int(lastn(16, int2bits(i))), s2i(i2s(bits2int(lastn(16, int2bits(i))))) = bits2int(lastn(16, int2bits(i))), ¬ i < ~32768 ∧ ¬ 32767 < i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: short-max-10: ⊦ 32767 < i → s2i(sho) ≠ i;%i0 ≠ 0, i0 < i ⊦ (* i) < j → (* i0) < j;% ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward)% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)