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Proof step 50 from proof sis-on-bits (previous step)

0 < bits2int(lastn(16, int2bits(i))), 16 ≤ # int2bits(i), 32767 < bits2int(lastn(16, int2bits(i))) ⊦ ¬ i < ~32768 ∧ ¬ 32767 < i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 51:
⊦ # bits = 16 → ¬ 32767 < bits2int(bits)

Rule argument

seq: ⊦ # bits = 16 → ¬ 32767 < bits2int(bits) subst: [bits] → [lastn(16, int2bits(i))] rotate: F spec: int2bits inst: name: bits2int16-01

Additional information

Used simplifier rules: ⊦ n ≤ # bits → # lastn(n, bits) = n; Used terms: lastn(16, int2bits(i))