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Proof step 1 from proof sis-sub-2pot (conclusion)

⊦ 0 ≤ i ∧ i < 65536 → s2i(i2s(i - 65536)) = s2i(i2s(i))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i < 65536, 0 ≤ i ⊦ s2i(i2s(i - 65536)) = s2i(i2s(i))

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)