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Proof step 2 from proof sis-sub-2pot (previous step)

i < 65536, 0 ≤ i ⊦ s2i(i2s(i - 65536)) = s2i(i2s(i))

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 3:
i = i0 + 65536, i < 65536, 0 ≤ i ⊦ s2i(i2s(i0)) = s2i(i2s(i))

Rule argument

seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [i, 65536, i0] rotate: T spec: int-abs inst: name: elim-sub

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: i, 65536, i0