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Proof step 14 from proof ubyte-inj (previous step)

256 + b2i(by) = b2i(by0), 0 ≤ b2i(by0), b2i(by) < 0 ⊦ by = by0

User applied rule insert lemma

And obtained the following new goals

Proof step 15:
⊦ ~128 ≤ b2i(by) ∧ b2i(by) ≤ 127
Proof step 16:
~128 ≤ b2i(by0) ∧ b2i(by0) ≤ 127, 256 + b2i(by) = b2i(by0), 0 ≤ b2i(by0), b2i(by) < 0 ⊦ by = by0

Rule argument

name: byte-range subst: [by] → [by0]

Additional information

Used terms: by0