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Proof step 16 from proof ubyte-inj (previous step)

~128 ≤ b2i(by0) ∧ b2i(by0) ≤ 127, 256 + b2i(by) = b2i(by0), 0 ≤ b2i(by0), b2i(by) < 0 ⊦ by = by0

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 2 flags: rotate, discard

Additional information

Used simplifier rules: byte-nle-02: i < ~128 ⊦ ¬ b2i(by) ≤ (* i);% ⊦ (* j) ≤ i0 + (* j0) ↔ j - j0 ≤ i0;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i;% ⊦ i + (* j) ≤ (* j0) ↔ i ≤ j0 - j;