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Proof step 1 from proof bits2bytes-len-01 (conclusion)

⊦ # bits % 8 = 0 ∧ bits ≠ [] → # bits2bytes(bits) = # bits / 8

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
# bits % 8 = 0 ⊦ bits = [], # bits2bytes(bits) = # bits / 8

Rule argument

Additional information