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Proof step 2 from proof bits2bytes-len-01 (previous step)

# bits % 8 = 0 ⊦ bits = [], # bits2bytes(bits) = # bits / 8

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ bits ≠ [] → # bits2bytes(bits) = (# bits - 1) / 8 + 1
Proof step 4:
bits ≠ [], # bits % 8 = 0 ⊦ bits = [], (# bits - 1) / 8 + 1 = # bits / 8

Rule argument

name: bits2bytes-len rotate: F subst: [bits] → [bits]

Additional information

Used terms: bits