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Proof step 5 from proof bits2bytes-len-01 (previous step)

# bits % 8 = 0 ⊦ bits = [], (# bits - 1) / 8 + 1 = # bits / 8

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ n ≠ 0 → (m % n = 0 ↔ (∃ n0. m = n0 * n))
Proof step 7:
8 ≠ 0, ∃ n0. # bits = n0 * 8 ⊦ bits = [], (# bits - 1) / 8 + 1 = # bits / 8

Rule argument

seq: ⊦ n ≠ 0 → (m % n = 0 ↔ (∃ n0. m = n0 * n)) subst: [n, m] → [8, # bits] rotate: F spec: nat-div inst: name: modex

Additional information

Used terms: 8, # bits