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Proof step 7 from proof bits2bytes-len-01 (previous step)

8 ≠ 0, ∃ n0. # bits = n0 * 8 ⊦ bits = [], (# bits - 1) / 8 + 1 = # bits / 8

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
# bits = n * 8 ⊦ bits = [], (n * 8 - 1) / 8 + 1 = n

Rule argument

Additional information

Used simplifier rules: ⊦ m * n = n * m;% ⊦ m0 * m * n = (m0 * m) * n;%n ≠ 0 ⊦ (m * n) / n = m;