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Proof step 8 from proof bits2bytes-len-01 (previous step)

# bits = n * 8 ⊦ bits = [], (n * 8 - 1) / 8 + 1 = n

User applied rule cut formula

And obtained the following new goals

Proof step 9:
n * 8 - 1 = (n - 1) * 8 + 7, # bits = n * 8 ⊦ bits = [], (n * 8 - 1) / 8 + 1 = n
Proof step 10:
# bits = n * 8 ⊦ n * 8 - 1 = (n - 1) * 8 + 7, bits = [], (n * 8 - 1) / 8 + 1 = n

Rule argument

fma: n * 8 - 1 = (n - 1) * 8 + 7

Additional information

Used formulas: n * 8 - 1 = (n - 1) * 8 + 7