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Proof step 7 from proof bits2bytes-mklist (previous step)

n % 8 = 0, n ≤ 8, ∀ n0. n0 < n → n0 % 8 = 0 → n0 = 0 ∨ bits2bytes(mklist(false, n0)) = mklist(i2b(0), n0 / 8) ⊦ bits2bytes(mklist(false, n)) = mklist(i2b(0), n / 8), n = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
⊦ # bits ≤ 8 → bits2bytes(bits) = i2b(bits2int(bits)) '
Proof step 9:
# mklist(false, n) ≤ 8, n % 8 = 0, n ≤ 8, ∀ n0. n0 < n → n0 % 8 = 0 → n0 = 0 ∨ bits2bytes(mklist(false, n0)) = mklist(i2b(0), n0 / 8) ⊦ i2b(bits2int(mklist(false, n))) ' = mklist(i2b(0), n / 8), n = 0

Rule argument

name: bits2bytes-base rotate: F subst: [bits] → [mklist(false, n)]

Additional information

Used simplifier rules: ⊦ # mklist(boolvar, n) = n;% ⊦ ¬ m ≤ n ↔ n < m;% ⊦ m ≤ n → (n < m ↔ false); Used terms: mklist(false, n)