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Proof step 9 from proof bits2bytes-mklist (previous step)

# mklist(false, n) ≤ 8, n % 8 = 0, n ≤ 8, ∀ n0. n0 < n → n0 % 8 = 0 → n0 = 0 ∨ bits2bytes(mklist(false, n0)) = mklist(i2b(0), n0 / 8) ⊦ i2b(bits2int(mklist(false, n))) ' = mklist(i2b(0), n / 8), n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
n % 8 = 0, n ≤ 8, ∀ n0. n0 < n → n0 % 8 = 0 → n0 = 0 ∨ bits2bytes(mklist(false, n0)) = mklist(i2b(0), n0 / 8) ⊦ n = 0, n / 8 = 1

Rule argument

Additional information

Used simplifier rules: ⊦ # mklist(boolvar, n) = n;% ⊦ mklist(by, n) = by ' ↔ n = 1;% ⊦ m ≠ 0 → bits2int(mklist(false, m)) = 0;