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Proof step 2 from proof byte2bits-mone (previous step)

⊦ byte2bits(i2b(~1)) = true ' + true ' + true ' + true ' + true ' + true ' + true ' + true '

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ byte2bits(by) = fillsgn(8, int2bits(b2i(by)))
Proof step 4:
⊦ fillsgn(8, int2bits(b2i(i2b(~1)))) = true ' + true ' + true ' + true ' + true ' + true ' + true ' + true '

Rule argument

name: byte2bits rotate: F subst: [by] → [i2b(~1)]

Additional information

Used terms: i2b(~1)