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Proof step 4 from proof byte2bits-mone (previous step)

⊦ fillsgn(8, int2bits(b2i(i2b(~1)))) = true ' + true ' + true ' + true ' + true ' + true ' + true ' + true '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
⊦ fillsgn(8, int2bits(~1)) = true ' + true ' + true ' + true ' + true ' + true ' + true ' + true '

Rule argument

Additional information

Used simplifier rules: ~128 ≤ i, i ≤ 127 ⊦ b2i(i2b((* i))) = i;