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Proof step 1 from proof bytes2bits-empty-01 (conclusion)

⊦ bytes2bits(bytes) = [] ↔ bytes = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
bytes2bits(bytes) = [] ⊦ bytes = []

Rule argument

Additional information

Used simplifier rules: bytes2bits-empty: ⊦ bytes2bits([]) = [];