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Proof step 2 from proof bytes2bits-empty-01 (previous step)

bytes2bits(bytes) = [] ⊦ bytes = []

User applied rule structural induction

And closed the goal!

Rule argument

indvar: bytes

Additional information

Used simplifier rules: bytes2bits-append: ⊦ bytes2bits(bytes + bytes0) = bytes2bits(bytes) + bytes2bits(bytes0);%bytes2bits-one: ⊦ bytes2bits(by ') = byte2bits(by);%byte2bits-empty: ⊦ byte2bits(by) ≠ [];%bytelist freely generated by [], +;;% ⊦ by + bytes = by ' + bytes;% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ ¬ bits + bits0 ≠ [] ↔ bits = [] ∧ bits0 = [];% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;