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Proof step 2 from proof bytes2bytes-identity-01 (previous step)

# bytes ≤ # int2bytes(bytes2int(bytes)) ⊦ bytes = [], int2bytes(bytes2int(bytes)) = bytes

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
⊦ bytes ≠ [] → # int2bytes(bytes2int(bytes)) ≤ # bytes
Proof step 4:
bytes ≠ [] → # int2bytes(bytes2int(bytes)) ≤ # bytes, # bytes ≤ # int2bytes(bytes2int(bytes)) ⊦ bytes = [], int2bytes(bytes2int(bytes)) = bytes

Rule argument

name: bytes2bytes-length subst: [bytes] → [bytes]

Additional information

Used terms: bytes