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Proof step 4 from proof bytes2bytes-identity-01 (previous step)

bytes ≠ [] → # int2bytes(bytes2int(bytes)) ≤ # bytes, # bytes ≤ # int2bytes(bytes2int(bytes)) ⊦ bytes = [], int2bytes(bytes2int(bytes)) = bytes

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
# bytes = # int2bytes(bytes2int(bytes)) ⊦ int2bytes(bytes2int(bytes)) = bytes, bytes = []

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ m;% ⊦ m ≤ n → (n ≤ m ↔ m = n);