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Proof step 4 from proof bytes2bytes-other (previous step)

⊦ bytes = [], b2i(bytes.first) = 0, b2i(bytes.first) = ~1, int2bytes(bits2int(bytes2bits(bytes))) = bytes

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ int2bytes(i) = bits2bytes(int2bits(i))
Proof step 6:
⊦ bytes = [], b2i(bytes.first) = 0, b2i(bytes.first) = ~1, bits2bytes(int2bits(bits2int(bytes2bits(bytes)))) = bytes

Rule argument

name: int2bytes rotate: F subst: [i] → [bits2int(bytes2bits(bytes))]

Additional information

Used terms: bits2int(bytes2bits(bytes))