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Proof step 6 from proof bytes2bytes-other (previous step)

⊦ bytes = [], b2i(bytes.first) = 0, b2i(bytes.first) = ~1, bits2bytes(int2bits(bits2int(bytes2bits(bytes)))) = bytes

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
bits ≠ [] ⊦ int2bits(bits2int(bits)) = sgn(bits)
Proof step 8:
bytes2bits(bytes) ≠ [] ⊦ bytes = [], b2i(bytes.first) = 0, b2i(bytes.first) = ~1, bits2bytes(sgn(bytes2bits(bytes))) = bytes

Rule argument

seq: bits ≠ [] ⊦ int2bits(bits2int(bits)) = sgn(bits) subst: [bits] → [bytes2bits(bytes)] rotate: F spec: int2bits inst: name: bits2bits-def

Additional information

Used simplifier rules: bytes2bits-empty-01: ⊦ bytes2bits(bytes) = [] ↔ bytes = []; Used terms: bytes2bits(bytes)