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Proof step 5 from proof bytes2bytes-zero (previous step)

bytes0 = by0 + bytes, b2i(by) = 0, b2i(by0) < 0 ⊦ int2bytes(bytes2int(by ' + bytes0)) = by ' + bytes0, bytes0 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
b2i(by) = 0, b2i(by0) < 0 ⊦ int2bytes(bytes2int(by ' + by0 ' + bytes)) = by ' + by0 ' + bytes

Rule argument

Additional information

Used simplifier rules: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ by ' + bytes ≠ [];% ⊦ by + bytes = by ' + bytes;