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Proof step 6 from proof bytes2bytes-zero (previous step)

b2i(by) = 0, b2i(by0) < 0 ⊦ int2bytes(bytes2int(by ' + by0 ' + bytes)) = by ' + by0 ' + bytes

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ bytes2int(bytes) = bits2int(bytes2bits(bytes))
Proof step 8:
b2i(by) = 0, b2i(by0) < 0 ⊦ int2bytes(bits2int(bytes2bits(by ' + by0 ' + bytes))) = by ' + by0 ' + bytes

Rule argument

name: bytes2int rotate: F subst: [bytes] → [by ' + by0 ' + bytes]

Additional information

Used terms: by ' + by0 ' + bytes